(49k^-1)^3/7k^-8

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Solution for (49k^-1)^3/7k^-8 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

k^-8*(((49*k^-1)^3)/7) = 0

16807*k^-11 = 0 // : 16807

k^-11 = 0

k należy do O

k belongs to the empty set

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